![please explain a=dv/dt = dv/dx = dx/dt = dv/dx =adx=vdv - Physics - Motion In A Straight Line - 2651959 | Meritnation.com please explain a=dv/dt = dv/dx = dx/dt = dv/dx =adx=vdv - Physics - Motion In A Straight Line - 2651959 | Meritnation.com](https://s3mn.mnimgs.com/img/shared/discuss_editlive/3079860/2012_07_12_18_12_11/mathmlequation2915202041970641358.png)
please explain a=dv/dt = dv/dx = dx/dt = dv/dx =adx=vdv - Physics - Motion In A Straight Line - 2651959 | Meritnation.com
![Question Video: Finding an Expression That Represents the Rate of Change of a Cube's Volume Using Related Rates | Nagwa Question Video: Finding an Expression That Represents the Rate of Change of a Cube's Volume Using Related Rates | Nagwa](https://media.nagwa.com/280178362646/en/thumbnail_l.jpeg)
Question Video: Finding an Expression That Represents the Rate of Change of a Cube's Volume Using Related Rates | Nagwa
![Find `(dy)/(dx)` using the rule `(dy)/(dx)=(dy)/(du)*(du)/(dv)*(dv)/(dx):` `y=cos^(-1) sqrt(2x-3)` - YouTube Find `(dy)/(dx)` using the rule `(dy)/(dx)=(dy)/(du)*(du)/(dv)*(dv)/(dx):` `y=cos^(-1) sqrt(2x-3)` - YouTube](https://i.ytimg.com/vi/x0sNd2zSv0M/maxresdefault.jpg)
Find `(dy)/(dx)` using the rule `(dy)/(dx)=(dy)/(du)*(du)/(dv)*(dv)/(dx):` `y=cos^(-1) sqrt(2x-3)` - YouTube
![Acceleration of particle moving in straight line can be written as `a=(dv )/(dt)=v(dv)/(dx)`. From t - YouTube Acceleration of particle moving in straight line can be written as `a=(dv )/(dt)=v(dv)/(dx)`. From t - YouTube](https://i.ytimg.com/vi/srrYsPvS7ZM/maxresdefault.jpg)